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A space r i g i d space b o d y space o f space m o m e n t space o f space i n e r t i a l space I space i s space p r o j e c t e d space w i t h space v e l o c i t y space V space m a k i n g space a n space a n g l e space o f space space space w i t h space
h o r i z o n t a l. space T h e space m a g n i t u d e space o f space a n g u l a r space m o m e n t u m space o f space t h e space p r o j e c t i l e space a b o u t space t h e space p o i n t space o f space p r o j e c t i o n space
text  when the body is at its maximum height is given by  end text fraction numerator I V cubed over denominator 2 square root of 2 g R squared end fraction text  where  end text straight R text  is the radius of the rigid  end text
b o d y. space T h e space r i g i d space b o d y space i s colon

  1. sphere 
  2. spherical shell 
  3. disc 
  4. none of these

The correct answer is: disc


    text  At highest point, velocity  end text equals V cos invisible function application 45 to the power of ring operator equals V divided by square root of 2
L equals m fraction numerator V over denominator square root of 2 end fraction times r perpendicular
text  Here  end text r subscript perpendicular equals h equals fraction numerator V squared sin squared invisible function application 45 to the power of ring operator over denominator 2 g end fraction equals fraction numerator V squared over denominator 4 g end fraction
table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell L equals fraction numerator m V cubed over denominator 4 square root of 2 g end fraction equals fraction numerator I V cubed over denominator 2 square root of 2 g R squared end fraction left parenthesis text  given  end text right parenthesis end cell row cell text  So  end text comma m over 2 equals I over R squared end cell row cell I equals 1 half m R squared end cell end table
I t space i s space a space d i s c

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