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Physics-

General

Easy

Question

A short solenoid of length 4 cm, radius 2 cm and 100 turns is placed inside and on the axis of a long solenoid of length 80 cm and 1500 turns. A current of 3 A flows through the short solenoid. The mutual inductance of two solenoids is

$2.96 \times 10^{- 4} H$
$5.3 \times 10^{- 5} H$
$3.52 \times 10^{- 3} H$
$8.3 \times 10^{- 5} H$

The correct answer is: $2.96 cross times 10 to the power of negative 4 end exponent H$

$M subscript 21 end subscript equals fraction numerator mu subscript 0 end subscript N subscript 1 end subscript N subscript 2 end subscript A subscript 2 end subscript over denominator l subscript 2 end subscript end fraction$
$therefore M subscript 21 end subscript equals fraction numerator table row cell open parentheses 4 cross times 3.14 cross times 10 to the power of negative 7 end exponent close parentheses cross times 1500 cross times 100 cross times end cell row cell open curly brackets 3.14 open parentheses 2 cross times 10 to the power of negative 2 end exponent close parentheses to the power of 2 end exponent close curly brackets end cell end table over denominator 80 cross times 10 to the power of negative 2 end exponent end fraction$
$M subscript 21 end subscript equals 2.96 cross times 10 to the power of negative 4 end exponent H$
$rightwards double arrow M subscript 12 end subscript equals M subscript 21 end subscript equals 2.96 cross times 10 to the power of negative 4 end exponent H$

Related Questions to study

The number of turns in primary coil of a transformer is 20 and the number of turns in the secondary is 10. If the voltage across the primary is 220 V, what is the voltage across the secondary?

The number of turns in primary coil of a transformer is 20 and the number of turns in the secondary is 10. If the voltage across the primary is 220 V, what is the voltage across the secondary?

Physics-General

$I f tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank x blank a n d tan invisible function application fraction numerator 5 pi over denominator 18 end fraction$ are in A.P. and $tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank y blank a n d tan invisible function application fraction numerator 7 pi over denominator 18 end fraction$ are also in A.P., then

$I f tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank x blank a n d tan invisible function application fraction numerator 5 pi over denominator 18 end fraction$ are in A.P. and $tan invisible function application fraction numerator pi over denominator 9 end fraction comma blank y blank a n d tan invisible function application fraction numerator 7 pi over denominator 18 end fraction$ are also in A.P., then

Sum of all the solutions in $open square brackets 0 comma blank 4 pi close square brackets$ of the equation $tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses$ is

Sum of all the solutions in $open square brackets 0 comma blank 4 pi close square brackets$ of the equation $tan invisible function application x plus cot invisible function application x plus 1 equals cos invisible function application open parentheses x plus fraction numerator pi over denominator 4 end fraction close parentheses$ is

parallel

If $blank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma$ then the number of values of $theta$ in the interval $left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis$ are

If $blank open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus tan invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta plus 2 to the power of tan to the power of 2 end exponent invisible function application theta end exponent equals 0 comma$ then the number of values of $theta$ in the interval $left parenthesis negative pi divided by 2 comma blank pi divided by 2 right parenthesis$ are

If $open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1$ and $theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I$ , then

If $open vertical bar 2 sin invisible function application theta minus c o s e c blank theta close vertical bar greater or equal than 1$ and $theta not equal to fraction numerator n pi over denominator 2 end fraction comma blank n element of I$ , then

If $S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma$ then

If $S equals open curly brackets x element of N blank colon 2 plus log subscript 2 end subscript invisible function application square root of x plus 1 end root greater than 1 minus log subscript 1 divided by 2 end subscript invisible function application square root of 4 minus x to the power of 2 end exponent end root close curly brackets comma$ then

parallel

$log subscript 4 end subscript invisible function application 18$ is

$log subscript 4 end subscript invisible function application 18$ is

If $sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma$ then $theta blank$ is equal to $blank open parentheses n element of Z close parentheses$

If $sin invisible function application 6 theta plus sin invisible function application 4 theta plus sin invisible function application 2 theta equals 0 comma$ then $theta blank$ is equal to $blank open parentheses n element of Z close parentheses$

The area of the circle and the area of a regular polygon of $n$ sides and of perimeter equal to that of the circle are in the ratio of

The area of the circle and the area of a regular polygon of $n$ sides and of perimeter equal to that of the circle are in the ratio of

parallel

$I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root$ is always equal to

$I f blank x element of open parentheses pi comma fraction numerator 3 pi over denominator 2 end fraction close parentheses comma blank t h e n blank 4 cos to the power of 2 end exponent invisible function application open parentheses fraction numerator pi over denominator 4 end fraction minus fraction numerator x over denominator 2 end fraction close parentheses plus square root of 4 sin to the power of 4 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x end root$ is always equal to

If $tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma$ then

If $tan invisible function application theta plus sin invisible function application theta equals m blank a n d tan invisible function application theta minus sin invisible function application theta equals n comma$ then

$I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript$ are two distinct roots of the equation $a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction$ is equal to

$I f blank x subscript 1 end subscript blank a n d blank x subscript 2 end subscript$ are two distinct roots of the equation $a cos invisible function application x plus b sin invisible function application x equals c comma blank t h e n tan invisible function application fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 2 end fraction$ is equal to

parallel

$I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o$

$I f fraction numerator sin invisible function application open parentheses x plus y close parentheses over denominator sin invisible function application open parentheses x minus y close parentheses end fraction equals fraction numerator a plus b over denominator a minus b end fraction comma blank t h e n fraction numerator tan invisible function application x over denominator tan invisible function application y end fraction blank i s blank e q u a l blank t o$

Which of the following is not the general solution of $2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?$

Which of the following is not the general solution of $2 to the power of cos invisible function application 2 x end exponent plus 1 equals 3.2 to the power of negative sin to the power of 2 end exponent invisible function application x end exponent ?$

In triangle $A B C comma$ base $B C$ and area of triangle $increment$ are fixed. Locus of the centroid of triangle $A B C$ is a straight line that is

In triangle $A B C comma$ base $B C$ and area of triangle $increment$ are fixed. Locus of the centroid of triangle $A B C$ is a straight line that is

parallel

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