Physics-
General
Easy

Question

A standing wave is created on a string of length 120 m and it is vibrating in 6th harmonic. Maximum possible amplititude of any particle is 10 cm and maximum possible velocity will be 10 cm/s. Choose the correct statement.

  1. Angular wave number of two waves will be p/20    
  2. Time period of any particle's SHM will be 4p sec    
  3. Any particle will have same kinetic energy as potential energy    
  4. Amplitude of interfering waves are 10 cm each.    

The correct answer is: Angular wave number of two waves will be p/20


    6 open parentheses fraction numerator lambda over denominator 2 end fraction close parentheses equals 120 rightwards double arrow lambda equals 40 rightwards double arrow k equals fraction numerator pi over denominator 20 end fraction rightwards double arrow A omega equals v subscript m a x end subscript rightwards double arrow omega equals 1 rightwards double arrow T equals 2 pi

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