Physics
Mechanics
Easy

Question

A string is holding a solid block below the surface of the liquid as shown in figure. Now if the system is given an upward constant acceleration a, then as compared to previous state.

  1. (A)  Tension is string will be open parentheses 1 plus a over g close parentheses times
  2. Tension in string will be open parentheses 1 minus a over g close parentheses times
  3. Upthrust force on block become open parentheses 1 plus a over g close parentheses times
  4. Upthrust force on block becomes open parentheses 1 minus a over g close parentheses times

The correct answer is: Upthrust force on block becomes open parentheses 1 minus a over g close parentheses times


    table attributes columnalign left end attributes row cell P subscript s equals fraction numerator M g over denominator A end fraction equals fraction numerator 3 cross times 10 over denominator pi open square brackets 16 cross times 10 to the power of negative 4 end exponent minus 1 cross times 10 to the power of negative 4 end exponent close square brackets end fraction end cell row cell equals fraction numerator 30 cross times 10 to the power of 4 over denominator pi cross times 15 end fraction equals 2 over pi cross times 10 to the power of 4 P a end cell end table
    According to Pascal law  P equals h rho g
    rightwards double arrow h equals fraction numerator P subscript s over denominator rho g end fraction equals fraction numerator 2 over pi cross times 10 to the power of 4 over denominator 10 cubed cross times 10 end fraction equals 2 over pi m

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