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Physics

Mechanics

Easy

Question

The little prince (the main character of the novel written by Antoine de Saint-Exupery) lives on the spherical planet named B-612, the density of which is 5200 kg/m³. The Little Prince noticed that if he quickens his pace. he feels himself lighter. When he reached the speed of 2m/s he became weightless, and began to orbit about the planet as a satellite. What is escape speed on the surface of planet?

$2 \sqrt{2} m / s$
$2 m / s$
$4 \sqrt{2} m / s$
$8 \sqrt{2} m / s$

The correct answer is: $2 square root of 2 m divided by s$

$text Orbital speed end text v subscript 0 equals square root of fraction numerator G m over denominator R end fraction end root 2 equals square root of fraction numerator G m over denominator R end fraction end root text Hence escape speed end text v subscript e equals square root of fraction numerator 2 G m over denominator R end fraction end root equals 2 square root of 2 straight m divided by straight s$

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