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Physics-

General

Easy

Question

Electric charge is uniformly distributed along a long straight wire of radius 1mm. The charge per cm length of the wire is Q coulomb. Another cylindrical surface of radius 50 cm and length 1m symmetrically encloses the wire as shown in the figure. The total electric flux passing through the cylindrical surface is

$\frac{Q}{ε_{0}}$
$\frac{100 Q}{ε_{0}}$
$\frac{10 Q}{(π ε_{0})}$
$\frac{100 Q}{(π ε_{0})}$

The correct answer is: $fraction numerator 100 Q over denominator epsilon subscript 0 end subscript end fraction$

Charge enclosed by cylindrical surface (length 100 cm) is $Q subscript e n c end subscript equals 100 Q.$ By applying Gauss's law $phi equals fraction numerator 1 over denominator epsilon subscript 0 end subscript end fraction left parenthesis Q subscript e n c. end subscript right parenthesis equals fraction numerator 1 over denominator epsilon subscript 0 end subscript end fraction left parenthesis 100 Q right parenthesis$

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