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Physics

Mechanics

Easy

Question

Four particles each of mass 1kg are at the four corners of square of side 1m. The M.I. of the system about a normal axis through centre of square is

$6 {kgm}^{2}$
$2 {kgm}^{2}$
$1.25 {kgm}^{2}$
$2.5 {kgm}^{2}$

The correct answer is: $2 kgm squared$

$I equals sum m r squared semicolon r equals fraction numerator l over denominator square root of 2 end fraction$

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