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If stack A with rightwards arrow on top=2 stack i with hat on top plus 3 stack j with hat on top plus 4 stack k with hat on top and stack B with rightwards arrow on top equals 4 stack i with hat on top plus 3 stack j with hat on top plus 2 stack k with hat on top, then angle between stack A with rightwards arrow on top and stack B with rightwards arrow on top is

  1. sin to the power of negative 1 end exponent invisible function application left parenthesis 25 divided by 29 right parenthesis  
  2. sin to the power of negative 1 end exponent invisible function application left parenthesis 29 divided by 25 right parenthesis  
  3. cos to the power of negative 1 end exponent invisible function application left parenthesis 25 divided by 29 right parenthesis  
  4. cos to the power of negative 1 end exponent invisible function application left parenthesis 29 divided by 25 right parenthesis  

The correct answer is: cos to the power of negative 1 end exponent invisible function application left parenthesis 25 divided by 29 right parenthesis


    costheta equals stack A with rightwards arrow on top bullet stack B with rightwards arrow on top divided by A B

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