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In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy E subscript 0 end subscriptand the radius r subscript 0 end subscriptof the first orbit will be (a subscript 0 end subscriptis the Bohr radius)

  1. E subscript 0 end subscript equals negative   27.2   e V semicolon   r subscript 0 end subscript equals a subscript 0 end subscript divided by 2    
  2. E subscript 0 end subscript equals negative   27.2   e V semicolon   r subscript 0 end subscript equals a subscript 0 end subscript    
  3. E subscript 0 end subscript equals negative 13.6   e V semicolon   r subscript 0 end subscript equals a subscript 0 end subscript divided by 2    
  4. E subscript 0 end subscript equals negative 13.6   e V semicolon   r subscript 0 end subscript equals a subscript 0 end subscript    

The correct answer is: E subscript 0 end subscript equals negative   27.2   e V semicolon   r subscript 0 end subscript equals a subscript 0 end subscript divided by 2


    Here radius of electron orbit r proportional to 1 divided by mand energy E µ m, where m is the mass of the electron.
    Hence energy of hypothetical atom
    E subscript 0 end subscript equals 2 cross times left parenthesis negative 13.6 e V right parenthesis equals negative 27.2 e V and radius r subscript 0 end subscript equals fraction numerator a subscript 0 end subscript over denominator 2 end fraction

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