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Question

In a magnetic field of 0.05 T, area of a coil changes from 101 c m to the power of 2 end exponent to 100 c m to the power of 2 end exponent without changing the resistance which is 2 capital omega. The amount of charge that flow during this period is

  1. 2.5 cross times 10 to the power of negative 6 end exponent blank c o u l o m b  
  2. 2 cross times 10 to the power of negative 6 end exponent blank c o u l o m b  
  3. 10 to the power of negative 6 end exponent blank c o u l o m b  
  4. 8 cross times 10 to the power of negative 6 end exponent blank c o u l o m b  

The correct answer is: 2.5 cross times 10 to the power of negative 6 end exponent blank c o u l o m b


    ϕ equals B A
    rightwards double arrow change in flux d ϕ equals B d A equals 0.05 open parentheses 101 minus 100 close parentheses 10 to the power of negative 4 end exponent
    equals 5 cross times 10 to the power of negative 6 end exponent W b
    Now, charge d Q equals fraction numerator d ϕ over denominator R end fraction equals fraction numerator 5 cross times 10 to the power of negative 6 end exponent over denominator 2 end fraction equals 2.5 cross times 10 to the power of negative 6 end exponent C

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