Physics-
General
Easy
Question
In a U–tube, if different liquids are filled then we can say that pressure at same level of same liquid is same. In a U–tube 20 cm of a liquid of density 
is on left hand side and 10 cm of another liquid of density 1.5 is on right hand side. In between them there is a third liquid of density 2. What is the value of h
- 5 cm
- 2.5 cm
- 2 cm
- 7.5 cm
The correct answer is: 2.5 cm
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If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – 
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Physics-General
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet = velocity of jet , density of liquid = , Mass of cart M = 10 kg: The time at which velocity of cart becomes 2m/s, is equal to:
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet = velocity of jet , density of liquid = , Mass of cart M = 10 kg: The time at which velocity of cart becomes 2m/s, is equal to:
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet = velocity of jet , density of liquid = , Mass of cart M = 10 kg: In the above problem, what is the acceleration of cart at this instant –
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
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If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet = velocity of jet , density of liquid = , Mass of cart M = 10 kg: Velocity of cart at t = 10 s. is equal to:
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If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
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