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Physics-

General

Easy

Question

In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced 3/4^th of the original length and the tension is changed. The factor by which the tension is to be changed is

1.2 m
1.8 m
2.1 m
8.1 m

The correct answer is: 8.1 m

Related Questions to study

The length of a sonometer wire AB is 100 cm, where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1:2:6

The length of a sonometer wire AB is 100 cm, where should the two bridges be placed from A to divide the wire in 3 segments whose fundamental frequencies are in the ratio of 1:2:6

Physics-General

The internal energy of a solid also increases when heat is transferred to it from its surroundings. A 5 kg solid bar is heated at atmospheric pressure. Its temperature increases from 20°C to 70°C. The linear expansion coefficient of solid bar is $1 cross times 10 to the power of negative 3 end exponent divided by C to the power of ring operator end exponent.$ The density of solid bar is $50 text end text k g divided by m to the power of 3 end exponent.$ The specific heat capacity of solid bar is $200 text end text J divided by K g C to the power of ring operator end exponent.$ The atmospheric pressure is $1 cross times 10 to the power of 5 end exponent text end text N divided by m to the power of 2 end exponent.$ The work done by the solid bar due to thermal expansion, under atmospheric pressure is

The internal energy of a solid also increases when heat is transferred to it from its surroundings. A 5 kg solid bar is heated at atmospheric pressure. Its temperature increases from 20°C to 70°C. The linear expansion coefficient of solid bar is $1 cross times 10 to the power of negative 3 end exponent divided by C to the power of ring operator end exponent.$ The density of solid bar is $50 text end text k g divided by m to the power of 3 end exponent.$ The specific heat capacity of solid bar is $200 text end text J divided by K g C to the power of ring operator end exponent.$ The atmospheric pressure is $1 cross times 10 to the power of 5 end exponent text end text N divided by m to the power of 2 end exponent.$ The work done by the solid bar due to thermal expansion, under atmospheric pressure is

Physics-General

Conservation of energy holds good even when substances in different states are mixed. When they are mixed, the change in state consumes energy of the high temperature substance without any change in temperature and then the mixture works for a common temperature. Sometimes, the energy lost by the container also to be accounted. When 1 g ice turns into water 80 calories of energy is consumed. After the change of state, the water formed will increase its temperature (Neglect heat capacity of the container) If in the first question, only 40 g water at $40 to the power of ring operator end exponent C$ is available with the container of water equivalent 80 g, then

Conservation of energy holds good even when substances in different states are mixed. When they are mixed, the change in state consumes energy of the high temperature substance without any change in temperature and then the mixture works for a common temperature. Sometimes, the energy lost by the container also to be accounted. When 1 g ice turns into water 80 calories of energy is consumed. After the change of state, the water formed will increase its temperature (Neglect heat capacity of the container) If in the first question, only 40 g water at $40 to the power of ring operator end exponent C$ is available with the container of water equivalent 80 g, then

Physics-General

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Work done in converting $1 g m$ of ice at $negative 10 to the power of ring operator end exponent C$ into steam at $100 to the power of ring operator end exponent C$ is

Work done in converting $1 g m$ of ice at $negative 10 to the power of ring operator end exponent C$ into steam at $100 to the power of ring operator end exponent C$ is

Physics-General

Two moles of an ideal monatomic gas undergoes the following cycle ABCA The work done per cycle is.

Two moles of an ideal monatomic gas undergoes the following cycle ABCA The work done per cycle is.

Physics-General

2 moles of an ideal gas undergoes a cyclic process as shown in figure. It is given that $T subscript 1 end subscript equals 325 text end text K comma text end text T subscript 2 end subscript equals 540 text end text K comma text end text T subscript 3 end subscript equals 900 text end text K comma text end text T subscript 4 end subscript equals 465 text end text K$ . Determine the work done on the gas by the surroundings in this cyclic process ? (universal gas constant is R)

2 moles of an ideal gas undergoes a cyclic process as shown in figure. It is given that $T subscript 1 end subscript equals 325 text end text K comma text end text T subscript 2 end subscript equals 540 text end text K comma text end text T subscript 3 end subscript equals 900 text end text K comma text end text T subscript 4 end subscript equals 465 text end text K$ . Determine the work done on the gas by the surroundings in this cyclic process ? (universal gas constant is R)

Physics-General

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An ideal gas is pumped into a rigid vessel whose walls are diathermic. In a certain time interval the pressure of the gas in the container becomes 4 times, the internal energy will ... in the interval. Best suitable option for the blank space is .

An ideal gas is pumped into a rigid vessel whose walls are diathermic. In a certain time interval the pressure of the gas in the container becomes 4 times, the internal energy will ... in the interval. Best suitable option for the blank space is .

Physics-General

The cylinder shown contains a gas. The piston is held fixed and the cylinder is heated. As a result pressure of gas increases, this happens because

The cylinder shown contains a gas. The piston is held fixed and the cylinder is heated. As a result pressure of gas increases, this happens because

Physics-General

The two processes are as shown in the figure. If $Q subscript 1 end subscript$ and $Q subscript 2 end subscript$ be the heat supplied to system in processes A and B respectively, then.

The two processes are as shown in the figure. If $Q subscript 1 end subscript$ and $Q subscript 2 end subscript$ be the heat supplied to system in processes A and B respectively, then.

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For a quasi-static process $p minus V$ curve is given as shown during the process as state changes from 1 to 2 , the work done by system on the surroundings is with respect to time.

For a quasi-static process $p minus V$ curve is given as shown during the process as state changes from 1 to 2 , the work done by system on the surroundings is with respect to time.

Physics-General

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process [5^19/13=10.5] The mixture is compressed adiabatically to 1/5 of its volume. Find the change in its adiabatic compresibility in terms of V and T

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process [5^19/13=10.5] The mixture is compressed adiabatically to 1/5 of its volume. Find the change in its adiabatic compresibility in terms of V and T

Physics-General

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process[5^19/13=10.5] If T is raised by 1k from 300k. Find the percentage change in volume.

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process[5^19/13=10.5] If T is raised by 1k from 300k. Find the percentage change in volume.

Physics-General

parallel

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process [5^19/13=10.5] Find the number of moles of gas $B$ in the gaseous mixture

A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas 'A' with $gamma equals open parentheses fraction numerator C p over denominator C v end fraction close parentheses equals fraction numerator 5 over denominator 3 end fraction$ and another gas 'B' with $gamma equals fraction numerator 7 over denominator 5 end fraction$ at a certain temperature T. The gram molecular weights of gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation $P V to the power of 19 divided by 13 end exponent equals$ constant in an adiabatic process [5^19/13=10.5] Find the number of moles of gas $B$ in the gaseous mixture

Physics-General

2k-mol of an ideal diatomic gas is enclosed in a vertical cylinder fitted with a piston and spring as shown in the figure. Initially the spring is compressed by 5 cm and then the electric heater starts supplying energy to the gas at constant rate of 100 J/S and due to conduction through walls of cylinder and radiation, 20 J/S has been lost to surroundings ( Take K=1000 N/m, $g equals 10 text end text m divided by s to the power of 2 end exponent$ atomospheric pressure, $P subscript o end subscript equals 10 to the power of 5 end exponent text end text N divided by m to the power of 2 end exponent$ , cross section area of piston $A subscript o end subscript equals 50 text end text c m to the power of 2 end exponent$ , mass of piston m=1 kg R=8.3kj mol k) Answer the given question based on this information.

Work done by the gas in 5 s is

2k-mol of an ideal diatomic gas is enclosed in a vertical cylinder fitted with a piston and spring as shown in the figure. Initially the spring is compressed by 5 cm and then the electric heater starts supplying energy to the gas at constant rate of 100 J/S and due to conduction through walls of cylinder and radiation, 20 J/S has been lost to surroundings ( Take K=1000 N/m, $g equals 10 text end text m divided by s to the power of 2 end exponent$ atomospheric pressure, $P subscript o end subscript equals 10 to the power of 5 end exponent text end text N divided by m to the power of 2 end exponent$ , cross section area of piston $A subscript o end subscript equals 50 text end text c m to the power of 2 end exponent$ , mass of piston m=1 kg R=8.3kj mol k) Answer the given question based on this information.

Work done by the gas in 5 s is

Physics-General

A rope hangs from a rigid support. A pulse is set by jiggling the bottom end. We want to design a rope in which velocity u of pulse is independent of z, the distance of the pulse from fixed end of the rope. If the rope is very long the desired function for mass per unit length m (z) in terms of $mu subscript 0 end subscript$ (mass per unit length of the rope at the top (z = 0) is given by

A rope hangs from a rigid support. A pulse is set by jiggling the bottom end. We want to design a rope in which velocity u of pulse is independent of z, the distance of the pulse from fixed end of the rope. If the rope is very long the desired function for mass per unit length m (z) in terms of $mu subscript 0 end subscript$ (mass per unit length of the rope at the top (z = 0) is given by

Physics-General

parallel

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