Physics-
General
Easy

Question

In the circuit shown below, the ac source has voltage V equals 20 cos invisible function application left parenthesis omega t right parenthesis volts with omega = 2000 rad/sec. the amplitude of the current will be nearest to

  1. 2 A    
  2. 3.3 A    
  3. 2 divided by square root of 5 A    
  4. square root of 5 A    

The correct answer is: 2 A


    R equals 6 plus 4 equals 10 capital omega
    X subscript L end subscript equals omega L equals 2000 cross times 5 cross times 1 0 to the power of negative 3 end exponent equals 10 capital omega
    X subscript C end subscript equals fraction numerator 1 over denominator omega C end fraction equals fraction numerator 1 over denominator 2000 cross times 50 cross times 1 0 to the power of negative 6 end exponent end fraction equals 10 capital omega
    therefore Z equals square root of R to the power of 2 end exponent plus left parenthesis X subscript L end subscript minus X subscript C end subscript right parenthesis to the power of 2 end exponent end root equals 10 capital omega
    Amplitude of current equals i subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction equals fraction numerator 20 over denominator 10 end fraction equals 2 A

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