Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

In the circuit shown below, the key $K$ is closed at $t equals 0$ . The current through the battery is

$\frac{V (R_{1} + R_{2})}{R_{1} R_{2}}$ at $t = 0$ and $\frac{V}{R_{2}}$ at $t = \infty$
$\frac{V (R_{1} + R_{2})}{\sqrt{R_{1}^{2} R_{2}^{2}}}$ at $t = 0$ and $\frac{V}{R_{2}}$ at $t = \infty$
$\frac{V}{R_{2}}$ at $t = 0$ and $\frac{V (R_{1} + R_{2})}{R_{1} R_{2}}$ at $t = \infty$
$\frac{V}{R_{2}}$ at $t = 0$ and $\frac{V (R_{1} + R_{2})}{\sqrt{R_{1}^{2} R_{2}^{2}}}$ at $t = \infty$

The correct answer is: $fraction numerator V over denominator R subscript 2 end subscript end fraction$ at $t equals 0$ and $fraction numerator V open parentheses R subscript 1 end subscript plus R subscript 2 end subscript close parentheses over denominator R subscript 1 end subscript R subscript 2 end subscript end fraction$ at $t equals infinity$

At $t equals 0$ inductor behaves as broken wire then $i equals fraction numerator V over denominator R subscript 2 end subscript end fraction$

At $t equals infinity$ Inductor behaves as conducting wire
$i equals fraction numerator V over denominator R subscript 2 end subscript R subscript 2 end subscript divided by left parenthesis R subscript 1 end subscript plus R subscript 2 end subscript right parenthesis end fraction equals fraction numerator V left parenthesis R subscript 1 end subscript plus R subscript 2 end subscript right parenthesis over denominator R subscript 1 end subscript R subscript 2 end subscript end fraction$

Related Questions to study

A coil of $N$ turns and mean cross-sectional area $A$ is rotating with uniform angular velocity $omega$ about an axis at right angle to uniform magnetic field $B$ . The induced e.m.f. $E$ in the coil will be

A coil of $N$ turns and mean cross-sectional area $A$ is rotating with uniform angular velocity $omega$ about an axis at right angle to uniform magnetic field $B$ . The induced e.m.f. $E$ in the coil will be

Physics-General

An aluminium ring $B$ faces an electromagnet $A$ . The current $I$ through $A$ can be altered

An aluminium ring $B$ faces an electromagnet $A$ . The current $I$ through $A$ can be altered
Physics-General

The adjoining figure shows two bulbs $B subscript 1 end subscript$ and $B subscript 2 end subscript$ , resistor $R$ and an inductor $L$ . When the switch $S$ is turned off

The adjoining figure shows two bulbs $B subscript 1 end subscript$ and $B subscript 2 end subscript$ , resistor $R$ and an inductor $L$ . When the switch $S$ is turned off
Physics-General

parallel

A step-down transformer is connected to $2400 blank v o l t s$ line and 80 amperes of current is found to flow in output load. The ratio of the turns in primary and secondary coil is 20:1. If transformer efficiency is 100%, then the current flowing in primary coil will be

A step-down transformer is connected to $2400 blank v o l t s$ line and 80 amperes of current is found to flow in output load. The ratio of the turns in primary and secondary coil is 20:1. If transformer efficiency is 100%, then the current flowing in primary coil will be

Physics-General

When a magnet is pushed in and out of a circular coil $C$ connected to a very senstitive galvanometer $G$ as shown in the adjoining diagram with a frequency $v$ , then

When a magnet is pushed in and out of a circular coil $C$ connected to a very senstitive galvanometer $G$ as shown in the adjoining diagram with a frequency $v$ , then
Physics-General

The mutual inductance between a primary and secondary circuits is $0.5 blank H$ . The resistances of the primary and the secondary circuits are $20 blank o h m s$ and $5 blank o h m s$ respectively. To generate a current of $0.4 blank A$ in the secondary, current in the primary must be changed at the rate of

The mutual inductance between a primary and secondary circuits is $0.5 blank H$ . The resistances of the primary and the secondary circuits are $20 blank o h m s$ and $5 blank o h m s$ respectively. To generate a current of $0.4 blank A$ in the secondary, current in the primary must be changed at the rate of

Physics-General

parallel

A metallic ring is dropped down, keeping its plane perpendicular to a constant and horizontal magnetic field. The ring enters the region of magnetic field at $t equals 0$ and completely emerges out at $t equals T s e c.$ The current in the ring varies as

A metallic ring is dropped down, keeping its plane perpendicular to a constant and horizontal magnetic field. The ring enters the region of magnetic field at $t equals 0$ and completely emerges out at $t equals T s e c.$ The current in the ring varies as

Physics-General

The radius of a circular plate is increasing at the rate of 0.01 cm/s when the radius is 12 cm. Then ,The rate at which the area increase, is

The radius of a circular plate is increasing at the rate of 0.01 cm/s when the radius is 12 cm. Then ,The rate at which the area increase, is

If the area of the triangle, included between the axes and any tangent to the curve $x y to the power of n end exponent equals a to the power of n plus 1 end exponent$ is constant, then the value of $n$ is

If the area of the triangle, included between the axes and any tangent to the curve $x y to the power of n end exponent equals a to the power of n plus 1 end exponent$ is constant, then the value of $n$ is

parallel

The fixed point $P$ on the curve $y equals x to the power of 2 end exponent minus 4 x plus 5$ such that the tangent at $P$ is perpendicular to the line $x plus 2 y minus 7 equals 0$ is given by

The fixed point $P$ on the curve $y equals x to the power of 2 end exponent minus 4 x plus 5$ such that the tangent at $P$ is perpendicular to the line $x plus 2 y minus 7 equals 0$ is given by

The function $f open parentheses x close parentheses equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c comma a to the power of 2 end exponent less or equal than 3 b blank h a s$

The function $f open parentheses x close parentheses equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c comma a to the power of 2 end exponent less or equal than 3 b blank h a s$

How many real solutions does the equation $x to the power of 7 end exponent plus 14 x to the power of 5 end exponent plus 16 x to the power of 3 end exponent plus 30 x minus 560 equals 0$ have?

How many real solutions does the equation $x to the power of 7 end exponent plus 14 x to the power of 5 end exponent plus 16 x to the power of 3 end exponent plus 30 x minus 560 equals 0$ have?

parallel

If $y equals x to the power of n end exponent comma$ then the ratio of relative errors in $y$ and $x$ is

If $y equals x to the power of n end exponent comma$ then the ratio of relative errors in $y$ and $x$ is

If a and b are positive numbers such that $a greater than b comma$ then the minimum value of $a sec invisible function application blank theta minus b tan invisible function application theta open parentheses 0 less than theta less than fraction numerator pi over denominator 2 end fraction close parentheses$ is

If a and b are positive numbers such that $a greater than b comma$ then the minimum value of $a sec invisible function application blank theta minus b tan invisible function application theta open parentheses 0 less than theta less than fraction numerator pi over denominator 2 end fraction close parentheses$ is

The side of an equilateral triangle is $´ a ´$ units and is increasing at the rate of $lambda blank u n i t s divided by s e c$ . The rate of increase of its area is

The side of an equilateral triangle is $´ a ´$ units and is increasing at the rate of $lambda blank u n i t s divided by s e c$ . The rate of increase of its area is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.