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Physics-

General

Easy

Question

Nuclear fission can be explained based on

Millikan’s oil drop method
Liquid drop model
Shell model
Bohr’s model

The correct answer is: Liquid drop model

Millikan oil drop method determines the charge on an electron. Liquid drop model explains nuclear fission, Shell model explains the stability of nuclei and Bohr’s model accounts for the stability of the atom and the line spectra of hydrogen atom.

Related Questions to study

$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

parallel

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

Physics-General

if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

parallel

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

parallel

$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

Cadmium rods are used in a nuclear reactor for

Cadmium rods are used in a nuclear reactor for

Physics-General

parallel

To determine the half- life of radioactive element, a student plots graph of ln $open vertical bar fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction close vertical bar v e r s u s$ t. Here $fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction$ is the rate of radioactive decay at time t. If the number of radioactive nuclei of this element decreases by a factor of $p$ after 4.16 yr, the value of $p$ is

To determine the half- life of radioactive element, a student plots graph of ln $open vertical bar fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction close vertical bar v e r s u s$ t. Here $fraction numerator d N blank left parenthesis t right parenthesis over denominator d t end fraction$ is the rate of radioactive decay at time t. If the number of radioactive nuclei of this element decreases by a factor of $p$ after 4.16 yr, the value of $p$ is

Physics-General

In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number as

In Bohr model of hydrogen atom, the force on the electron depends on the principal quantum number as

Physics-General

Assertion : All the radioactive elements are ultimately converted in lead.
Reason : All the elements above lead are unstable.

Assertion : All the radioactive elements are ultimately converted in lead.
Reason : All the elements above lead are unstable.

Physics-General

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