Physics
Grade-9
Easy
Question
Resistors of resistances 10 Ω, 20 Ω, 30 Ω are connected in parallel so that the combination carries a current of 11 A. Potential difference across the combination is
- 60 V
- 30 V
- 120 V
- 6 V
Hint:
When the resistors are connected in parallel, the resistance can be calculated as- 
and potential difference across all the resistors is the same.
And we can calculate potential difference using Ohm's law, V=IR
The correct answer is: 60 V
When the resistors of resistances 10 Ω, 20 Ω, and 30 Ω are connected in parallel and the combination carries a current of 11 A, the potential difference across the combination is 60V.
- The potential difference in a parallel combination of resistors is the sum of all the resistances.
- The resistances of the parallel combination are 10Ω, 20Ω, and 30Ω, and the combination of all can give the potential difference.
- RT = 5.45 Ω
- Applying Ohm's law, V= IR,
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