Physics-
General
Easy

Question

The current in the circuit shown in the figure, considering ideal diode is

  1. 20 A    
  2. 2 cross times 10 to the power of negative 3 end exponent A    
  3. 200 A    
  4. 2 cross times 10 to the power of negative 4 end exponent A    

The correct answer is: 2 cross times 10 to the power of negative 3 end exponent A


    Potential difference across diode
    = 3.2 – 3 = 0.2 V
    therefore Current through diode
    i equals fraction numerator 0.2 over denominator 100 end fraction equals 2 cross times 10 to the power of negative 3 end exponent A

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