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Physics-

General

Easy

Question

The current through a $4.6 blank H$ inductor is shown in the following graph. The induced emf during the time interval $t equals 5 blank m i l l i minus s e c$ to $6 blank m i l l i minus s e c$ will be

$10^{3} V$
$- 23 \times 10^{3} V$
$23 \times 10^{3} V$
Zero

The correct answer is: $23 cross times 10 to the power of 3 end exponent blank V$

Rate of decay of current between $t equals 5 blank m s$ to $6 blank m s equals fraction numerator d i over denominator d t end fraction equals negative$ (Slope of the line $B C$ )
$equals negative open parentheses fraction numerator 5 over denominator 1 cross times 10 to the power of negative 3 end exponent end fraction close parentheses equals negative 5 cross times 10 to the power of 3 end exponent A divided by s$ . Hence induced emf
$e equals negative L fraction numerator d i over denominator d t end fraction equals negative 4.6 cross times open parentheses negative 5 cross times 10 to the power of 3 end exponent close parentheses equals 23 cross times 10 to the power of 3 end exponent V$

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