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General
Easy

Question

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

  1. 13.6   e V    
  2. plus fraction numerator 13.6 over denominator 9 end fraction e V    
  3. negative fraction numerator 13.6 over denominator 3 end fraction e V    
  4. negative fraction numerator 3 over denominator 13.6 end fraction e V    

The correct answer is: plus fraction numerator 13.6 over denominator 9 end fraction e V


    Energy required to knock out the electron in the nth orbitequals plus fraction numerator 13.6 over denominator n to the power of 2 end exponent end fraction e V Þ E subscript 3 end subscript equals plus fraction numerator 13.6 over denominator 9 end fraction e V.

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