Physics-
General
Easy

Question

The graph for an alloy of paramagnetic nature is shown in Fig. The curie constant is, then

  1. 57 K    
  2. 2.8 cross times 10 to the power of negative 3 end exponent K    
  3. 570 K    
  4. 17.5 cross times 10 to the power of negative 3 end exponent K    

The correct answer is: 57 K


    X equals C cross times fraction numerator 1 over denominator T end fraction equals fraction numerator 0.4 over denominator 7 cross times 1 0 to the power of negative 3 end exponent end fraction equals 57 K

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