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Question

Two identical bar magnets with a length 10 cm and weight 50 gm-weight are arranged freely with their like poles facing in a inverted vertical glass tube. The upper magnet hangs in the air above the lower one so that the distance between the nearest pole of the magnet is 3mm. Pole strength of the poles of each magnet will be

  1. 6.64 amp ' m    
  2. 2 amp ' m    
  3. 10.25 amp ' m    
  4. None of these    

The correct answer is: 6.64 amp ´ m


    The weight of upper magnet should be balanced by the repulsion between the two magnet
    therefore   fraction numerator mu over denominator 4 pi end fraction. fraction numerator m to the power of 2 end exponent over denominator r to the power of 2 end exponent end fraction equals 50 g m minus w t
    rightwards double arrow 1 0 to the power of negative 7 end exponent cross times fraction numerator m to the power of 2 end exponent over denominator left parenthesis 9 cross times 1 0 to the power of negative 6 end exponent right parenthesis end fraction equals 50 cross times 1 0 to the power of negative 3 end exponent cross times 9.8
    rightwards double arrow m equals 6.64 a m p cross times m

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