Physics-
General
Easy

Question

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y equals 8 t minus 5 t to the power of 2 end exponent metre and x equals 6 t metre, where t is in second. The velocity with which the projectile is projected, is

  1. 14 blank m s to the power of negative 1 end exponent  
  2. 10 blank m s to the power of negative 1 end exponent  
  3. 8 blank m s to the power of negative 1 end exponent  
  4. 6 blank m s to the power of negative 1 end exponent  

The correct answer is: 10 blank m s to the power of negative 1 end exponent


    x equals open parentheses u c o s theta close parentheses t equals 6
    u c o s theta equals fraction numerator x over denominator t end fraction equals 6
    y equals open parentheses u s i n theta close parentheses t equals negative fraction numerator 1 over denominator 2 end fraction g t to the power of 2 end exponent
    y equals 8 t minus 5 t to the power of 2 end exponent ⟹ u s i n theta equals 8
    u equals 10 m divided by s

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