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The minimum and maximum distances of a satellite from the centre of the earth are 2R and 4R, respectively, where R is the radius of the earth and Mis the mass of the earth.
The radius of curvature at the point of minimum distance is

  1. fraction numerator 8 R over denominator 3 end fraction
  2. fraction numerator 5 R over denominator 3 end fraction
  3. fraction numerator 4 R over denominator 3 end fraction
  4. fraction numerator 7 R over denominator 3 end fraction

The correct answer is: fraction numerator 8 R over denominator 3 end fraction


    fraction numerator m v subscript 1 superscript 2 over denominator r end fraction equals fraction numerator G M m over denominator left parenthesis 2 R right parenthesis squared end fraction

    r equals fraction numerator 4 v subscript 1 superscript 2 R squared over denominator G M end fraction equals fraction numerator 8 R over denominator 3 end fraction space(
    putting value of v1)

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