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Question

The nuclear reaction 2 H plus to the power of 2 end exponent H rightwards arrow to the power of 4 end exponent H e (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

  1. Fusion reaction releasing 24 MeV energy    
  2. Fusion reaction absorbing 24 MeV energy    
  3. Fission reaction releasing 0.0258 MeV energy    
  4. Fission reaction absorbing 0.0258 MeV energy    

The correct answer is: Fusion reaction releasing 24 MeV energy


    Total mass of reactants
    equals left parenthesis 2.0141 right parenthesis cross times 2 equals 4.0282   a m u
    Total mass of products equals 4.0024   a m u
    Mass defect equals 4.0282   a m u minus 4.0024   a m u
    equals 0.0258   a m u
    thereforeEnergy releasedE equals 931 cross times 0.0258 equals 24   M e V

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