Physics-
General
Easy

Question

The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is

  1. Greater than T    
  2. Less than T    
  3. Equal to T    
  4. Cannot be compared    

The correct answer is: Greater than T


    Inside the mine g decreases
    hence from T equals 2 pi square root of fraction numerator l over denominator g end fraction end root; T increase

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