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Physics-

General

Easy

Question

The resistance and inductance of series circuit are $5 capital omega$ and $20 H$ respectively. At the instant of closing the switch, the current is increasing at the rate $4 A divided by s$ . The supply voltage is

$20 V$
$80 V$
$120 V$
$100 V$

The correct answer is: $80 blank V$

$i equals i subscript 0 end subscript open parentheses 1 minus e to the power of fraction numerator R t over denominator L end fraction end exponent close parentheses rightwards double arrow fraction numerator d i over denominator d t end fraction equals negative i subscript 0 end subscript open parentheses negative fraction numerator R over denominator L end fraction close parentheses e to the power of fraction numerator R t over denominator L end fraction end exponent equals fraction numerator i subscript 0 end subscript R over denominator L end fraction. e to the power of fraction numerator R t over denominator L end fraction end exponent$
At $t equals 0 semicolon fraction numerator d i over denominator d t end fraction equals fraction numerator i subscript 0 end subscript R over denominator L end fraction equals fraction numerator E over denominator L end fraction rightwards double arrow 4 equals fraction numerator E over denominator 20 end fraction rightwards double arrow E equals 80 blank V$

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