Physics-
General
Easy

Question

The temperature drop through a two layer furnace wall is null. Each layer is of equal area of cross–section. Which of the following action(s) will result in lowering the temperature null of the interface?

  1. By increasing the thermal conductivity of outer layer    
  2. By increasing the thermal conductivity of inner layer    
  3. By increasing thickness of outer layer    
  4. By increasing thickness of inner layer    

The correct answer is: By increasing thickness of inner layer


    Rate of heat flow null
    Now, we can see that q can be decreased by increasing thermal conductivity of outer layer null and thickness of inner layernull.

    Related Questions to study

    General
    Physics-

    An irregular rod of same uniform material as shown in figure is conducting heat at a steady rate. The temperature gradient at various sections versus area of cross section graph will be

    An irregular rod of same uniform material as shown in figure is conducting heat at a steady rate. The temperature gradient at various sections versus area of cross section graph will be

    Physics-General
    General
    Physics-

    Figure shows the variation of the internal energy U with density r of one mole of an ideal monatomic gas for thermodynamic cycle ABCA. Here process AB is a part of rectangular hyperbola :-

    Figure shows the variation of the internal energy U with density r of one mole of an ideal monatomic gas for thermodynamic cycle ABCA. Here process AB is a part of rectangular hyperbola :-

    Physics-General
    General
    Physics-

    Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume null versus Q. The temperature of the gas is (use nulln 9 = 2 and R= 25/3 J/mol-K)

    Suppose 0.5 mole of an ideal gas undergoes an isothermal expansion as energy is added to it as heat Q. Graph shows the final volume null versus Q. The temperature of the gas is (use nulln 9 = 2 and R= 25/3 J/mol-K)

    Physics-General
    parallel
    General
    Physics-

    Figure demonstrates a polytropic process (i.e. null = constant) for an ideal gas. The work done by the gas will be in process AB is

    Figure demonstrates a polytropic process (i.e. null = constant) for an ideal gas. The work done by the gas will be in process AB is

    Physics-General
    General
    Physics-

    The gas left in the vessel will be 2g of hydrogen i.e. number of molesnull

    The gas left in the vessel will be 2g of hydrogen i.e. number of molesnull

    Physics-General
    General
    Physics-

    A vessel contains 14 g (7 moles) of hydrogen and 96 g (3 moles) of oxygen at STP. Chemical reaction is induced by passing electric spark in the vessel till one of the gases is consumed. The temperature is brought back to it's starting value 273 K. The pressure in the vessel is-

    A vessel contains 14 g (7 moles) of hydrogen and 96 g (3 moles) of oxygen at STP. Chemical reaction is induced by passing electric spark in the vessel till one of the gases is consumed. The temperature is brought back to it's starting value 273 K. The pressure in the vessel is-

    Physics-General
    parallel
    General
    Physics-

    A fine steel wire of length 4m is fixed rigidly in a heavy brass frame as shown in figure. It is just taut at null. The tensile stress developed in steel wire if whole system is heated to null is :–

    A fine steel wire of length 4m is fixed rigidly in a heavy brass frame as shown in figure. It is just taut at null. The tensile stress developed in steel wire if whole system is heated to null is :–

    Physics-General
    General
    Physics-

    Figures shows the expansion of a 2m long metal rod with temperature. The volume expansion coefficient of the metal is :–

    Figures shows the expansion of a 2m long metal rod with temperature. The volume expansion coefficient of the metal is :–

    Physics-General
    General
    Physics-

    The figure shows two thin rods, one made of aluminum null and the other of steel null. Each rod has the same length and the same initial temperature. They are attached at one end to two separate immovable walls. Temperature of both the rods is increased by the same amount, until the gap between the rods vanishes. Where do the rods meet when the gap vanishes?

    The figure shows two thin rods, one made of aluminum null and the other of steel null. Each rod has the same length and the same initial temperature. They are attached at one end to two separate immovable walls. Temperature of both the rods is increased by the same amount, until the gap between the rods vanishes. Where do the rods meet when the gap vanishes?

    Physics-General
    parallel
    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – F equals rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent left square bracket 1 minus c o s invisible function application theta right square bracket Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet equals 2 cross times 10 to the power of negative 4 end exponent text end text m to the power of 2 end exponent velocity of jet V subscript 0 end subscript equals 10 text end text m divided by s e c, density of liquid equals 1000 text end text k g divided by m to the power of 3 end exponent comma M a s s of cart equals M equals 10 text end text k g. The power supplied to the cart, when its velocity becomes 5 m/sec., is equal to :

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – F equals rho A open parentheses V subscript 0 end subscript minus u close parentheses to the power of 2 end exponent left square bracket 1 minus c o s invisible function application theta right square bracket Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet equals 2 cross times 10 to the power of negative 4 end exponent text end text m to the power of 2 end exponent velocity of jet V subscript 0 end subscript equals 10 text end text m divided by s e c, density of liquid equals 1000 text end text k g divided by m to the power of 3 end exponent comma M a s s of cart equals M equals 10 text end text k g. The power supplied to the cart, when its velocity becomes 5 m/sec., is equal to :

    Physics-General
    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. The time at which velocity of cart becomes 2 m/sec, is equal to

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. The time at which velocity of cart becomes 2 m/sec, is equal to

    Physics-General
    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. In the above problem, what is the acceleration of cart at this instant –

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. In the above problem, what is the acceleration of cart at this instant –

    Physics-General
    parallel
    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. Velocity of cart at t = 10 sec. is equal to :

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. Velocity of cart at t = 10 sec. is equal to :

    Physics-General
    General
    Physics-

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. Initially null the force on the cart is equal to :

    on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes – null Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :

    Given cross-section area of jet null velocity of jet null, density of liquid null of cart null. Initially null the force on the cart is equal to :

    Physics-General
    General
    Physics-

    Given T-P curve for three processes. If initial and final pressure are same for all processes then work done in process 1,2 and 3 is null respectively. Correct order is

    Given T-P curve for three processes. If initial and final pressure are same for all processes then work done in process 1,2 and 3 is null respectively. Correct order is

    Physics-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.