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Question

The velocity of a body of mass 20 kg decreases from 20 blank m s to the power of negative 1 end exponent t o blank 5 blank m s to the power of negative 1 end exponent in a distance of 100 m. Force on the body is

  1. negative 27.5 blank N  
  2. negative 47.5 blank N  
  3. negative 37.5 blank N  
  4. negative 67.5 blank N  

The correct answer is: negative 37.5 blank N


    Using Newton’s equation of motion
    v to the power of 2 end exponent equals u to the power of 2 end exponent plus 2 a s
    therefore blank open parentheses 5 close parentheses to the power of 2 end exponent equals open parentheses 20 close parentheses to the power of 2 end exponent plus 2 open parentheses a close parentheses 100
    Or blank a equals negative fraction numerator 400 minus 25 over denominator 200 end fraction equals negative fraction numerator 375 over denominator 200 end fraction m s to the power of negative 2 end exponent
    Therefore, fore F equals m a s s blank m blank cross times a c c e l e r a t i o n blank a
    equals 20 cross times open parentheses negative fraction numerator 375 over denominator 200 end fraction close parentheses equals negative 37.5 blank N

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