Physics-
General
Easy

Question

Three long, straight and parallel wires carrying currents are arranged as shown in figure. The force experienced by 10 cm length of wire Q is

  1. 1.4 cross times 1 0 to the power of negative 4 end exponent N towards the right    
  2. 1.4 cross times 1 0 to the power of negative 4 end exponent N towards the left    
  3. 2.6 cross times 1 0 to the power of negative 4 end exponent N to the right    
  4. 2.6 cross times 1 0 to the power of negative 4 end exponent N to the left    

The correct answer is: 1.4 cross times 1 0 to the power of negative 4 end exponent N towards the right


    Force on wire Q due to wire P is
    F subscript P end subscript equals 1 0 to the power of negative 7 end exponent cross times fraction numerator 2 cross times 30 cross times 10 over denominator 0.1 end fraction cross times 0.1 equals 6 cross times 1 0 to the power of negative 5 end exponent N (Towards left)

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