Physics-
General
Easy

Question

Two capacitors A and B are connected in series with a battery as shown in the figure. When the switch S is closed and the two capacitors get charged fully, then

  1. The potential difference across the plates of A is 4V and across the plates of B is 6V    
  2. The potential difference across the plates of A is 6V and across the plates of B is 4V    
  3. The ratio of electrical energies stored in A and B is 2 : 3    
  4. The ratio of charges on A and B is 3 : 2    

The correct answer is: The potential difference across the plates of A is 6V and across the plates of B is 4V


    In series combination of capacitors, voltage distributes on them, in the reverse ratio of their capacitance i.e. fraction numerator V subscript A end subscript over denominator V subscript B end subscript end fraction equals fraction numerator 3 over denominator 2 end fraction ......(i)
    Also VA + VB = 10 .......(ii)
    On solving (i) and (ii) VA = 6V, VB = 4V

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