Physics-
General
Easy

Question

Two capacitors C1 and C2 = 2C1 are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and C1 holds charge Q. The switch is closed. At steady state, the charge on each capacitor will be

  1. Q comma 2 Q    
  2. Q divided by 32 Q divided by 3    
  3. 3 Q divided by 23 Q    
  4. 2 Q divided by 34 Q divided by 3    

The correct answer is: Q divided by 32 Q divided by 3


    In steady state charge on C1 is Q subscript 1 end subscript equals open parentheses fraction numerator C subscript 1 end subscript over denominator C subscript 1 end subscript plus C subscript 2 end subscript end fraction close parentheses cross times Q equals fraction numerator Q over denominator 3 end fraction
    and charge on C2 is Q subscript 2 end subscript equals open parentheses fraction numerator C subscript 2 end subscript over denominator C subscript 1 end subscript plus C subscript 2 end subscript end fraction close parentheses. Q equals fraction numerator 2 over denominator 3 end fraction Q

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