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Physics

Fluid-Mechanics

Easy

Question

Two droplets merge with each other and forms a large droplet. In this process

Energy is liberated
Energy is absorbed
Neither liberated nor absorbed
Some mass is converted into energy

The correct answer is: Energy is liberated

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The potential energy of a molecule on the surface of liquid compared to one inside the liquid is

The potential energy of a molecule on the surface of liquid compared to one inside the liquid is

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Energy needed in breaking a drop of radius R into n drops of radii r is given by

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The force required to take away a flat circular plate of radius 2 cm from the surface of water, will be (the surface tension of water is 70 dyne/cm)

The force required to take away a flat circular plate of radius 2 cm from the surface of water, will be (the surface tension of water is 70 dyne/cm)

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A wooden stick 2m long is floating on the surface of water. The surface tension of water 0.07 N/m. By putting soap solution on one side of the sticks the surface tension is reduced to 0.06 N/m. The net force on the stick will be

A wooden stick 2m long is floating on the surface of water. The surface tension of water 0.07 N/m. By putting soap solution on one side of the sticks the surface tension is reduced to 0.06 N/m. The net force on the stick will be

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The force required to separate two glass plates of area $10 to the power of negative 2 end exponent m squared$ with a film of water 0.05 mm thick between them, is (Surface tension of water is $open 70 cross times 10 to the power of negative 3 end exponent N divided by m close parentheses$

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It is easy to wash clothes in hot water because its

It is easy to wash clothes in hot water because its

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A 10 cm long wire is placed horizontally on the surface of water and is gently pulled up with a force of 2 ×10^-2N to keep the wire in equilibrium. The surface tension, in Nm^-1, of water is

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With regard to dependence of quantities given in column I and II, match the following :

Column - I

Column - II

i.
Young's modules of a substance
a.
Depends on temperature

ii.
Bulk modulus of substance
b.
Depends on length

iii.
Modulus of rigidity of a substance
c.
Depends on area of across section

iv.
Volume of a substance
d.
Depends on the nature of material

With regard to dependence of quantities given in column I and II, match the following :

Column - I

Column - II

i.
Young's modules of a substance
a.
Depends on temperature

ii.
Bulk modulus of substance
b.
Depends on length

iii.
Modulus of rigidity of a substance
c.
Depends on area of across section

iv.
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d.
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Match the following

Column - I

Column - II

i.
Splitting of bigger drop into small droplets
a.
Temperature increases

ii.
Formation of bigger drop from small droplets
b.
Temperature in creases

iii.
Spraying of liquid
c.
Surface energy increases

iv.

d.
Surface energy decrease

Match the following

Column - I

Column - II

i.
Splitting of bigger drop into small droplets
a.
Temperature increases

ii.
Formation of bigger drop from small droplets
b.
Temperature in creases

iii.
Spraying of liquid
c.
Surface energy increases

iv.

d.
Surface energy decrease

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Match the following

Column - I

Column - II

longitudinal stress
a.
Volume changes

Shear stress
b.
Shape changes

Volume changes
c.
Volume does not change

Tensile stress
d.
Shape does not change

Match the following

Column - I

Column - II

longitudinal stress
a.
Volume changes

Shear stress
b.
Shape changes

Volume changes
c.
Volume does not change

Tensile stress
d.
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n Column L a uniform bar of uniform cross-sectional area under the application of forces is shown in the figure and in Column II, some effects/phenomena are given. Match the entries of Column I with the entries of Column II.

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i.
a.
Uniform stresses developed in the rod

ii.
b.
Non- uniform stresses developed in the rod

iii.
c.
Compressive stress developed

iv.
d.
Tensile stresses developed

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Column - I

Column - II

i.
a.
Uniform stresses developed in the rod

ii.
b.
Non- uniform stresses developed in the rod

iii.
c.
Compressive stress developed

iv.
d.
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Molecular forces exist between the molecules of a liquid in a container. The molecules on the surface have unequal force leading to a tension on the surface. If this is not compensated by a farce, the equilibrium of the liquid will be a difficult task. This leads to an excess pressure on the surface. The nature of the meniscus can inform us of the direction of the excess pressure. The angle of contact of the liquid decided by the forces between the molecules, air-and container can make the angle of contact.
If the excess pressure in a soap bubble is p, the excess pressure in an air bubble is

Molecular forces exist between the molecules of a liquid in a container. The molecules on the surface have unequal force leading to a tension on the surface. If this is not compensated by a farce, the equilibrium of the liquid will be a difficult task. This leads to an excess pressure on the surface. The nature of the meniscus can inform us of the direction of the excess pressure. The angle of contact of the liquid decided by the forces between the molecules, air-and container can make the angle of contact.
If the excess pressure in a soap bubble is p, the excess pressure in an air bubble is

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Molecular forces exist between the molecules of a liquid in a container. The molecules on the surface have unequal force leading to a tension on the surface. If this is not compensated by a farce, the equilibrium of the liquid will be a difficult task. This leads to an excess pressure on the surface. The nature of the meniscus can inform us of the direction of the excess pressure. The angle of contact of the liquid decided by the forces between the molecules, air-and container can make the angle of contact.
The direction of the excess pressure in the meniscus of a liquid of angle of contact $2 pi divided by 3$ is

Molecular forces exist between the molecules of a liquid in a container. The molecules on the surface have unequal force leading to a tension on the surface. If this is not compensated by a farce, the equilibrium of the liquid will be a difficult task. This leads to an excess pressure on the surface. The nature of the meniscus can inform us of the direction of the excess pressure. The angle of contact of the liquid decided by the forces between the molecules, air-and container can make the angle of contact.
The direction of the excess pressure in the meniscus of a liquid of angle of contact $2 pi divided by 3$ is

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A steel bolt of cross-sectional area $A subscript b equals 5 cross times 10 to the power of negative 5 end exponent straight m squared$ is passed through a cylindrical tube made of aluminium. Cross-sectional area of the tube material is $A subscript t equals 10 to the power of negative 4 end exponent m squared$ and its length is l =50 cm. The bolt is just taut to that there is no stress in the bolt and temperature of the assembly increases through $straight capital delta theta equals 10 to the power of ring operator straight C$ . Given, coefficient of linear thermal expansion of steel, $alpha subscript b equals 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
.
Young 's modulus of steel $Y subscript b equals 2 cross times 10 to the power of ′′ N divided by m squared$
Young's modulus of $A l comma Y subscript t equals 10 to the power of 11 N divided by m squared$ ,coefficient of
linear thermal expansion of $A l alpha subscript t equals 2 cross times 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
The compressive stress in tube is

A steel bolt of cross-sectional area $A subscript b equals 5 cross times 10 to the power of negative 5 end exponent straight m squared$ is passed through a cylindrical tube made of aluminium. Cross-sectional area of the tube material is $A subscript t equals 10 to the power of negative 4 end exponent m squared$ and its length is l =50 cm. The bolt is just taut to that there is no stress in the bolt and temperature of the assembly increases through $straight capital delta theta equals 10 to the power of ring operator straight C$ . Given, coefficient of linear thermal expansion of steel, $alpha subscript b equals 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
.
Young 's modulus of steel $Y subscript b equals 2 cross times 10 to the power of ′′ N divided by m squared$
Young's modulus of $A l comma Y subscript t equals 10 to the power of 11 N divided by m squared$ ,coefficient of
linear thermal expansion of $A l alpha subscript t equals 2 cross times 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
The compressive stress in tube is

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