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Physics-

General

Easy

Question

Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A 15 kg weight is attached to the rope at the midpoint which now no longer remains horizontal. The minimum tension required to completely straighten the rope is

15 kg
12/2 kg
5 kg
Infinitely large

hint Hint:

2TsinX=mg

The correct answer is: Infinitely large

When a string is fixed horizontally (by champing its free ends) and loaded at the middle, then for the equilibrium of point $P$

$2 T sin invisible function application theta equals W$
i.e., $T equals fraction numerator W over denominator 2 sin invisible function application theta end fraction$
Tension in the string will be maximum when $sin invisible function application theta$ is minimum, i.e., $theta equals 0 degree$ or $sin invisible function application theta equals 0$ and then $T equals infinity$ . However, as every string can bear a maximum finite tension (lesser than breaking strength), this situation cannot be realized practically. We conclude that a string can never remain horizontal when loaded at the middle howsoever great may be the tension applied

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