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Vibrating tuning fork of frequency n is placed near the open end of a long cylindrical tube. The tube has a side opening and is fitted with a movable reflecting piston. As the piston is moved through 8.75 cm, the intensity of sound changes from a maximum to minimum. If the speed of sound is 350 m/s. Then n is

  1. 500 Hz    
  2. 1000 Hz    
  3. 2000 Hz    
  4. 4000 Hz    

The correct answer is: 1000 Hz


    When the piston is moved through a distance of 8.75cm, the path difference produced is 2 cross times 8.75 c m equals 17.5 c m. This must be equal tofraction numerator lambda over denominator 2 end fraction for maximum to change to minimum. \ fraction numerator lambda over denominator 2 end fraction equals 17.5cm Þ lambda equals 35 c m equals 0.35 m
    So, v equals n lambda Þ n equals fraction numerator v over denominator lambda end fraction equals fraction numerator 350 over denominator 0.35 end fraction equals 1000 H z

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