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Easy

Question

Arrange the following in descending order :
cube root of 17 comma space square root of 12 comma space cube root of 21 comma space square root of 18

The correct answer is: Use LCM property


    Complete step by step solution:
    Here we can write, cube root of 17 equals 17 to the power of 1 third end exponent comma horizontal ellipsis square root of 12 equals 12 to the power of 1 half end exponent horizontal ellipsis cube root of 21 equals 21 to the power of 1 third end exponent, and square root of 18 equals 18 to the power of 1 half end exponent
    On taking the LCM of 2,3 we have LCM as 6.
    So,                                   not stretchy rightwards double arrow 17 to the power of 1 third end exponent equals 17 to the power of fraction numerator 1 cross times 2 over denominator 3 cross times 2 end fraction end exponent equals 17 to the power of 2 over 6 end exponent
    not stretchy rightwards double arrow open parentheses 17 squared close parentheses to the power of 1 over 6 end exponent equals 289 to the power of 1 over 6 end exponent  (Since ) open open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent close parentheses
    Likewise,                         not stretchy rightwards double arrow 12 to the power of 1 half end exponent equals 12 to the power of fraction numerator 1 cross times 3 over denominator 2 cross times 3 end fraction end exponent equals 12 to the power of 3 over 6 end exponent horizontal ellipsis
    not stretchy rightwards double arrow open parentheses 12 cubed close parentheses to the power of 1 over 6 end exponent equals 1728 to the power of 1 over 6 end exponent space of 1em open parentheses text  Since  end text open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent close parentheses(Since )
    Likewise,                         21 to the power of 1 third end exponent equals 21 to the power of fraction numerator 1 cross times 2 over denominator 3 cross times 2 end fraction end exponent equals 21 to the power of 2 over 6 end exponent
    not stretchy rightwards double arrow open parentheses 21 squared close parentheses to the power of 1 over 6 end exponent equals 441 to the power of 1 over 6 end exponent space of 1em open parentheses text  Since  end text open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent close parentheses
    not stretchy rightwards double arrow 18 to the power of 1 half end exponent equals 18 to the power of fraction numerator 1 cross times 3 over denominator 2 cross times 3 end fraction end exponent equals 18 to the power of 3 over 6 end exponent horizontal ellipsis
    not stretchy rightwards double arrow open parentheses 18 cubed close parentheses to the power of 1 over 6 end exponent equals 5832 to the power of 1 over 6 end exponent space of 1em text  Since  end text open parentheses a to the power of b close parentheses to the power of c equals a to the power of b c end exponent
    Now, we have ,                 289 to the power of 1 over 6 end exponent comma 1728 to the power of 1 over 6 end exponent comma 441 to the power of 1 over 6 end exponent and 5832 to the power of 1 over 6 end exponent horizontal ellipsis
    So, here ascending order is 289 less than 441 less than 1728 less than 5832
    not stretchy rightwards double arrow 289 to the power of 1 over 6 end exponent less than 441 to the power of 1 over 6 end exponent less than 1728 to the power of 1 over 6 end exponent less than 5832 to the power of 1 over 6 end exponent
    not stretchy rightwards double arrow 17 to the power of 1 third end exponent less than 21 to the power of 1 third end exponent less than 12 to the power of 1 half end exponent less than 18 to the power of 1 half end exponent
    not stretchy rightwards double arrow cube root of 17 less than cube root of 21 less than cube root of 12 less than fifth root of 18




     

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