Chemistry-
General
Easy

Question

Concrete is produced from a mixture of cement, water and small stones. Small amount of gypsum, C a S O subscript 4 times 2 H subscript 2 O is added in cement production to improve the subsequent hardening of concrete. The elevated temperature during the production of cement may lead to the formation of unwanted hemihydrate
C a S O subscript 4 times 1 half H subscript 2 O according to reaction,
C a S O subscript 4 times 2 H subscript 2 O open parentheses s close parentheses rightwards arrow C a S O subscript 4 times 1 half H subscript 2 O open parentheses s close parentheses plus 3 over 2 H subscript 2 O left parenthesis g right parenthesis
The increment subscript f end subscript H to the power of ⊖ end exponentofC a S O subscript 4 times 2 H subscript 2 O open parentheses s close parentheses comma blank C a S O subscript 4 times 1 half H subscript 2 O open parentheses s close parentheses comma H subscript 2 O left parenthesis g right parenthesis are negative 2021.0 blank k J blank m o l to the power of negative 1 end exponent comma blank minus 1575.0 k J blank m o l to the power of negative 1 end exponent and negative 241.8 blank k J blank m o l to the power of negative 1 end exponent respectively. The respective values of their standard entropies are 194.0, 130.0 and 188.0 blank J blank K to the power of negative 1 end exponent blank m o l to the power of negative 1 end exponent. The values of R equals 8.314 blank J blank K to the power of negative 1 end exponent m o l to the power of negative 1 end exponent equals 0.0831 blank L blank b a r blank m o l to the power of negative 1 end exponent K to the power of negative 1 end exponent
Answer the following questions on the basis of above information
Heat change occurring during conversion of 1 kg of C a S O subscript 4 times 2 H subscript 2 O left parenthesis s right parenthesis (molar mass 172 g m o l to the power of negative 1 end exponent) of C a S O subscript 4 times 1 half H subscript 2 O left parenthesis s right parenthesis is equal to

  1. 484 blank k J blank m o l to the power of negative 1 end exponent    
  2. 400 blank k J    
  3. negative 484.0 blank k J blank m o l to the power of negative 1 end exponent    
  4. negative 1000 blank k J    

The correct answer is: 484 blank k J blank m o l to the power of negative 1 end exponent


    increment H to the power of ⊖ end exponent equals increment H subscript blank P end subscript superscript ⊖ end superscript minus increment H subscript blank R end subscript superscript ⊖ end superscript semicolon blank(for 1 mol)
    equals open square brackets negative 1575.0 blank k J blank m o l to the power of negative 1 end exponent minus fraction numerator 3 over denominator 2 end fraction cross times 241.8 close square brackets
    negative left square bracket negative 2021.0 blank k J blank m o l to the power of negative 1 end exponent right square bracket
    equals plus 83.3 blank k J blank m o l to the power of negative 1 end exponent
    For 1 kg C a S O subscript 4 end subscript times 2 H subscript 2 end subscript O
    Number of moles equals fraction numerator 1000 over denominator 172 end fraction equals 5.81
    thereforeHeat change for 5.81 mol ofblank C a S O subscript 4 end subscript times 2 H subscript 2 end subscript O
    equals 5.81 cross times 83.3 blank k J blank m o l to the power of negative 1 end exponent
    equals 484 blank k J blank m o l to the power of negative 1 end exponent

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