Chemistry-
General
Easy
Question
Figure shows a graph in where K is rate constant and T is temperature. The straight line BC has slope, and an intercept of 5 on y-axis. Thus , the energy of activation is:
- 2.303×2cal
- 2/2.303cal
- 2cal
- None of these
The correct answer is: 2cal
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The progress of the reaction can be best described by :
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