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Chemistry-

General

Easy

Question

For which of the process, $increment$ S is negative ?

$H_{2 (g)} \to 2 H_{(g)}$
$N_{2 (g)} (1 a t m) \to N_{2 (g)} (8 a t m)$
$2 {S O}_{3 (g)} \to 2 {S O}_{2 (g)} + O_{2 (g)}$
$C_{(diamond)} \to C_{(graphite)}$

The correct answer is: $N subscript 2 left parenthesis g right parenthesis end subscript left parenthesis 1 a t m right parenthesis rightwards arrow N subscript 2 left parenthesis g right parenthesis end subscript left parenthesis 8 a t m right parenthesis$

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$2 H subscript 2 left parenthesis g right parenthesis end subscript plus O subscript 2 left parenthesis g right parenthesis end subscript rightwards arrow 2 H subscript 2 end subscript O subscript left parenthesis 1 right parenthesis end subscript$ and $increment$ G = -ve Then the reaction is

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$M g S O subscript 4 left parenthesis s right parenthesis end subscript plus a q times rightwards arrow M g S O subscript 4 left parenthesis a q right parenthesis end subscript capital delta H equals negative 84 K blank text cals end text$ , $increment$ H of the reaction is known as

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For the following reaction $H subscript left parenthesis a q right parenthesis end subscript superscript plus end superscript plus O H subscript left parenthesis a q right parenthesis end subscript superscript minus end superscript rightwards arrow H subscript 2 end subscript O subscript left parenthesis 1 right parenthesis end subscript semicolon capital delta H equals negative Q comma$ Where $increment$ H represents

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