Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

The end product (B) formed in the reaction

${C H}_{2} = {C H C H}_{2} {N H}_{2}$
$H_{2} N {({C H}_{2})}_{4} {N H}_{2}$
${C H}_{3} N H {({C H}_{2})}_{2} {N H C H}_{3}$
$N C {({C H}_{2})}_{2} C N$

The correct answer is: $C H subscript 3 end subscript N H open parentheses C H subscript 2 end subscript close parentheses subscript 2 end subscript N H C H subscript 3 end subscript$

Related Questions to study

The major product formed in the reaction is –

The major product formed in the reaction is –

chemistry-General

The end product (B) formed in the reaction is -

The end product (B) formed in the reaction is -

chemistry-General

The IUPAC name of the following compound is –

The IUPAC name of the following compound is –

chemistry-General

parallel

The functional groups of (B) and (C) respectively are-

The functional groups of (B) and (C) respectively are-

chemistry-General

C and D in the sequence are -

C and D in the sequence are -

chemistry-General

Compound is a

Compound is a

chemistry-General

parallel

The diagram (figure) shows a venturimeter, through which water is flowing. The speed of water at X is 2 cm/s. The speed of water at Y (taking g = 1000 $c m divided by s to the power of 2 end exponent$ ) is :–

The diagram (figure) shows a venturimeter, through which water is flowing. The speed of water at X is 2 cm/s. The speed of water at Y (taking g = 1000 $c m divided by s to the power of 2 end exponent$ ) is :–

physics-General

In the figure below is shown the flow of liquid through a horizontal pipe. Three tubes A, B and C are connected to the pipe. The radii of the tubes, A, B and C at the junction are respectively 2 cm, 1 cm. and 2 cm. It can be said that the

In the figure below is shown the flow of liquid through a horizontal pipe. Three tubes A, B and C are connected to the pipe. The radii of the tubes, A, B and C at the junction are respectively 2 cm, 1 cm. and 2 cm. It can be said that the

physics-General

A body floats in a liquid contained in a beaker. The whole system is shown in figure falling under gravity. The up thrust on the body due to liquid is :–

A body floats in a liquid contained in a beaker. The whole system is shown in figure falling under gravity. The up thrust on the body due to liquid is :–

physics-General

parallel

Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four times that in B. The ratio of the liquid thrust at the base of A to that at the base of B is :–

Two vessels A and B have the same base area and contain water to the same height, but the mass of water in A is four times that in B. The ratio of the liquid thrust at the base of A to that at the base of B is :–

physics-General

The differential coefficient of $f left parenthesis log invisible function application x right parenthesis comma text where end text f left parenthesis x right parenthesis equals log invisible function application x$ is

The differential coefficient of $f left parenthesis log invisible function application x right parenthesis comma text where end text f left parenthesis x right parenthesis equals log invisible function application x$ is

Let $f left parenthesis x right parenthesis equals e to the power of x comma g left parenthesis x right parenthesis equals sin to the power of negative 1 end exponent invisible function application x text and end text h left parenthesis x right parenthesis equals f left square bracket g left parenthesis x right parenthesis right square bracket comma text then end text fraction numerator h to the power of straight prime left parenthesis x right parenthesis over denominator h left parenthesis x right parenthesis end fraction$ is equal to

Let $f left parenthesis x right parenthesis equals e to the power of x comma g left parenthesis x right parenthesis equals sin to the power of negative 1 end exponent invisible function application x text and end text h left parenthesis x right parenthesis equals f left square bracket g left parenthesis x right parenthesis right square bracket comma text then end text fraction numerator h to the power of straight prime left parenthesis x right parenthesis over denominator h left parenthesis x right parenthesis end fraction$ is equal to

parallel

If $f left parenthesis x right parenthesis equals fraction numerator g left parenthesis x right parenthesis plus g left parenthesis negative x right parenthesis over denominator 2 end fraction plus fraction numerator 2 over denominator left ceiling h left parenthesis x right parenthesis plus h left parenthesis negative x right parenthesis right square bracket to the power of negative 1 end exponent end fraction$ where g and are differentiable function, then $f to the power of straight prime left parenthesis 0 right parenthesis$ is

If $f left parenthesis x right parenthesis equals fraction numerator g left parenthesis x right parenthesis plus g left parenthesis negative x right parenthesis over denominator 2 end fraction plus fraction numerator 2 over denominator left ceiling h left parenthesis x right parenthesis plus h left parenthesis negative x right parenthesis right square bracket to the power of negative 1 end exponent end fraction$ where g and are differentiable function, then $f to the power of straight prime left parenthesis 0 right parenthesis$ is

If $f left parenthesis x right parenthesis$ and $straight g left parenthesis straight x right parenthesis$ are two functions with $g left parenthesis x right parenthesis equals x minus 1 over x text and fog end text left parenthesis x right parenthesis equals x cubed minus 1 over x cubed text , then end text f to the power of straight prime left parenthesis x right parenthesis text is end text$

If $f left parenthesis x right parenthesis$ and $straight g left parenthesis straight x right parenthesis$ are two functions with $g left parenthesis x right parenthesis equals x minus 1 over x text and fog end text left parenthesis x right parenthesis equals x cubed minus 1 over x cubed text , then end text f to the power of straight prime left parenthesis x right parenthesis text is end text$

$fraction numerator d over denominator d x end fraction sin to the power of negative 1 end exponent invisible function application open parentheses x square root of 1 minus x end root plus square root of x square root of open 1 minus x squared close parentheses end root close$ is equal to

$fraction numerator d over denominator d x end fraction sin to the power of negative 1 end exponent invisible function application open parentheses x square root of 1 minus x end root plus square root of x square root of open 1 minus x squared close parentheses end root close$ is equal to

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.