Chemistry-
General
Easy

Question

The free energy profile for the transformation of A in to G is shown below.

The slowest step in the forward direction:

  1. A to C    
  2. C to E    
  3. E to G    
  4. C to F    

The correct answer is: A to C

Related Questions to study

General
chemistry-

The free energy profile for the transformation of A in to G is shown below.

The overall reaction is :

The free energy profile for the transformation of A in to G is shown below.

The overall reaction is :

chemistry-General
General
chemistry-

The reaction S subscript 2 end subscript O subscript 8 end subscript superscript 2 minus end superscript plus 3 I to the power of minus end exponent rightwards arrow 2 S O subscript 4 end subscript superscript 2 minus end superscript plus I subscript 3 end subscript superscript minus end superscriptis of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as ' a ' and 'b' respectively and taking x as the concentration of the triodide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are

The general differential equation for the above reaction is

The reaction S subscript 2 end subscript O subscript 8 end subscript superscript 2 minus end superscript plus 3 I to the power of minus end exponent rightwards arrow 2 S O subscript 4 end subscript superscript 2 minus end superscript plus I subscript 3 end subscript superscript minus end superscriptis of first order both with respect to the persulphate and iodide ions. Taking the initial concentration as ' a ' and 'b' respectively and taking x as the concentration of the triodide at time t a differential rate equation can be written. Two suggested mechanisms for the reaction are

The general differential equation for the above reaction is

chemistry-General
General
chemistry-

Figure shows a graph in l o g subscript 10 end subscript invisible function application K v s fraction numerator 1 over denominator text end text T end fraction where K is rate constant and T is temperature. The straight line BC has slope, T a n invisible function application theta equals negative fraction numerator 1 over denominator 2.303 end fraction and an intercept of 5 on y-axis. Thus E subscript a end subscript, the energy of activation is:

Figure shows a graph in l o g subscript 10 end subscript invisible function application K v s fraction numerator 1 over denominator text end text T end fraction where K is rate constant and T is temperature. The straight line BC has slope, T a n invisible function application theta equals negative fraction numerator 1 over denominator 2.303 end fraction and an intercept of 5 on y-axis. Thus E subscript a end subscript, the energy of activation is:

chemistry-General
parallel
General
chemistry-

For an exothermic chemical process occurring in two steps as :
i) A+B→X (slow)
ii) X→AB( fast right parenthesis
The progress of the reaction can be best described by :

For an exothermic chemical process occurring in two steps as :
i) A+B→X (slow)
ii) X→AB( fast right parenthesis
The progress of the reaction can be best described by :

chemistry-General
General
chemistry-

With respect to the figure given below which of the following statement is correct

With respect to the figure given below which of the following statement is correct

chemistry-General
General
chemistry-

Mark correct statement about given graph:

Mark correct statement about given graph:

chemistry-General
parallel
General
chemistry-

The heats of combustion of carbon, hydrogen and acetylene are -394K.J, -286K.J and -1301 K.J respectively. Calculate heat of formation of C subscript 2 end subscript H subscript 2 end subscript

The heats of combustion of carbon, hydrogen and acetylene are -394K.J, -286K.J and -1301 K.J respectively. Calculate heat of formation of C subscript 2 end subscript H subscript 2 end subscript

chemistry-General
General
chemistry-

For the adsorption of solution on a solid surface fraction numerator x over denominator m end fraction equals k c to the power of 1 divided by n end exponent Adsorption isotherm of l o g invisible function application open parentheses fraction numerator x over denominator m end fraction close parentheses l o g invisible function application C was found of the type (Fig) This is when

For the adsorption of solution on a solid surface fraction numerator x over denominator m end fraction equals k c to the power of 1 divided by n end exponent Adsorption isotherm of l o g invisible function application open parentheses fraction numerator x over denominator m end fraction close parentheses l o g invisible function application C was found of the type (Fig) This is when

chemistry-General
General
physics-

For the same total mass which of the following will have the largest moment of inertia about an axis passing through its centre of mass and perpendicular to the plane of the body

For the same total mass which of the following will have the largest moment of inertia about an axis passing through its centre of mass and perpendicular to the plane of the body

physics-General
parallel
General
chemistry-

Thchangithstatohybridizatioof asteriskecarboin thfollowinreaction is-

Thchangithstatohybridizatioof asteriskecarboin thfollowinreaction is-

chemistry-General
General
chemistry-

The geometrical arrangement and shape of I3 arrespectively

The geometrical arrangement and shape of I3 arrespectively

chemistry-General
General
physics-

A rigid lamina is rotating about an axis passing Perpendiuclar to its plane through point O as shown in figure. The angular velocity of point B w.r.t. A is

A rigid lamina is rotating about an axis passing Perpendiuclar to its plane through point O as shown in figure. The angular velocity of point B w.r.t. A is

physics-General
parallel
General
chemistry-

Thcorrecstatemenfothreaction NH +H+→NH+

Thcorrecstatemenfothreaction NH +H+→NH+

chemistry-General
General
chemistry-

Correcstatement regarding thireaction BF3+NH3¾→[F3B¬NH3]

Correcstatement regarding thireaction BF3+NH3¾→[F3B¬NH3]

chemistry-General
General
physics-

STATEMENT-1 : No external force acts on system of two spheres which undergo a perfectly elastic head on collision. The minimum kinetic energy of this system is zero if the net momentum of this system is zero
STATEMENT-2 : In any two body system undergoing perfectly elastic head on collision, at the instant of maximum deformation, the complete kinetic energy of the system is converted to deformation potential energy of the system.

STATEMENT-1 : No external force acts on system of two spheres which undergo a perfectly elastic head on collision. The minimum kinetic energy of this system is zero if the net momentum of this system is zero
STATEMENT-2 : In any two body system undergoing perfectly elastic head on collision, at the instant of maximum deformation, the complete kinetic energy of the system is converted to deformation potential energy of the system.

physics-General
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