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    Chemistry-
    General
    Easy

    Question

    The IUPAC name of the compound is -

    1. 1-Phenyl-1-acetyloxy ethane    
    2. 1-Acetoxyethyl benzene    
    3. 1-Phenylethyl ethanoate    
    4. 1-Methylbenzyl acetate    

    The correct answer is: 1-Phenyl-1-acetyloxy ethane

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    The IUPAC name for

    The IUPAC name for

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    The IUPAC name of the given compound is -

    The IUPAC name of the given compound is -

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    What will be the order of reactivity of the following alcohols towards concentrated HCI ?
    I) 
    II) 
    III) 
    IV) 

    What will be the order of reactivity of the following alcohols towards concentrated HCI ?
    I) 
    II) 
    III) 
    IV) 

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    The major product formed in the reaction is

    The major product formed in the reaction is

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    In the given reaction

    In the given reaction

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    In the following hydration the major alcohol product formed is -

    In the following hydration the major alcohol product formed is -

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    A tertiary alcohol is obtained when C H subscript 3 end subscript M g I reacts with-

    A tertiary alcohol is obtained when C H subscript 3 end subscript M g I reacts with-

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    The missing structures A and B in the reaction sequence:
    ; A&B are given by the set -

    The missing structures A and B in the reaction sequence:
    ; A&B are given by the set -

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    In the reaction,  the product obtained will be -

    In the reaction,  the product obtained will be -

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    One litre of a gas collected at NTP will occupy at 2 atmospheric. pressure and 27 to the power of 0 C:

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    blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

    blank subscript 83 end subscript superscript 214 end superscript B i stack ⟶ with alpha text -emission  end text on top A stack ⟶ with beta text -emission  end text on top B stack ⟶ with beta minus text  cmission  end text on top C stack ⟶ with beta text -emission  end text on top D stack ⟶ with alpha text -emission  end text on top E E' is.an element of stable nucleus What is the element 'E'?

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    Consider the following nuclear reactions: table row cell blank subscript 92 end subscript superscript 238 end superscript M ⟶ blank subscript y end subscript superscript x end superscript N plus 2 blank subscript 2 end subscript superscript 4 end superscript H e end cell row cell blank subscript y end subscript superscript x end superscript N ⟶ blank subscript B end subscript superscript A end superscript L plus 2 beta to the power of plus end exponent end cell end table the number of neutrons present in the element 'L' is:

    Consider the following nuclear reactions: table row cell blank subscript 92 end subscript superscript 238 end superscript M ⟶ blank subscript y end subscript superscript x end superscript N plus 2 blank subscript 2 end subscript superscript 4 end superscript H e end cell row cell blank subscript y end subscript superscript x end superscript N ⟶ blank subscript B end subscript superscript A end superscript L plus 2 beta to the power of plus end exponent end cell end table the number of neutrons present in the element 'L' is:

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    A radioactive element decays by parallel path as given below :
    table attributes columnalign right end attributes row cell A stack ⟶ with lambda subscript 1 end subscript on top B lambda subscript 1 end subscript end cell cell blank equals 1.8 cross times 10 to the power of negative 2 end exponent s e c to the power of negative 1 end exponent end cell row cell 2 A stack ⟶ with lambda subscript 2 end subscript on top B lambda subscript 2 end subscript end cell cell blank equals 10 to the power of negative 3 end exponent s e c to the power of negative 1 end exponent end cell end table
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    A radioactive element decays by parallel path as given below :
    table attributes columnalign right end attributes row cell A stack ⟶ with lambda subscript 1 end subscript on top B lambda subscript 1 end subscript end cell cell blank equals 1.8 cross times 10 to the power of negative 2 end exponent s e c to the power of negative 1 end exponent end cell row cell 2 A stack ⟶ with lambda subscript 2 end subscript on top B lambda subscript 2 end subscript end cell cell blank equals 10 to the power of negative 3 end exponent s e c to the power of negative 1 end exponent end cell end table
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    In the radioactive change, blank subscript negative Z end subscript superscript A end superscript P ⟶ blank subscript z plus 1 end subscript superscript A end superscript Q ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript R ⟶ blank subscript Z minus 1 end subscript superscript A minus 4 end superscript S the radiations emitted in sequence are:

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    (A) blank subscript 92 end subscript superscript 238 end superscript U left parenthesis I I I B right parenthesis stack ⟶ with negative alpha on top A stack ⟶ with negative alpha on top B stack ⟶ with negative beta on top C
    (R) Element B will be of IIA grou

    (A) blank subscript 92 end subscript superscript 238 end superscript U left parenthesis I I I B right parenthesis stack ⟶ with negative alpha on top A stack ⟶ with negative alpha on top B stack ⟶ with negative beta on top C
    (R) Element B will be of IIA grou

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