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Chemistry-

General

Easy

Question

Which order is correct in spectrochemical series of ligands -

${Cl}^{-} < F^{-} < C_{2} O_{4}^{2 -} < {NO}_{2}^{-} < {CN}^{-}$
${C N}^{-} < C_{2} O_{4}^{2 -} < {C l}^{-} > {N O}_{2} < F^{-}$
$C_{2} O_{4}^{2 -} < F^{-} < {Cl}^{-} > {NO}_{2}^{- 2} < {CN}^{-}$
$F^{-} < {C l}^{-} < {N O}_{2}^{-} < {C N}^{-} < C_{2} O_{4}^{2 -}$

The correct answer is: $Cl to the power of minus less than straight F to the power of minus less than straight C subscript 2 straight O subscript 4 superscript 2 minus end superscript less than NO subscript 2 superscript minus less than CN to the power of minus$

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