Solution for the question - domain of definition of the functionf(x)=(3)/(4-x^(2))+log_(10)(x^(3)-x), is (-1,0)uu(1,2)uu(2,oo) '/> (1,2)uu(2,oo) '/> (-1,0)uu(1,2) '/>

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Question

Domain of definition of the function $f left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x squared end fraction plus log subscript 10 invisible function application open parentheses x cubed minus x close parentheses comma text is end text$

$(1, 2)$
$(- 1, 0) \cup (1, 2)$
$(1, 2) \cup (2, \infty)$
$(- 1, 0) \cup (1, 2) \cup (2, \infty)$

The correct answer is: $left parenthesis negative 1 comma 0 right parenthesis union left parenthesis 1 comma 2 right parenthesis union left parenthesis 2 comma straight infinity right parenthesis$

Since, $f left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x squared end fraction plus log subscript 10 invisible function application open parentheses x cubed minus x close parentheses$
For domain of $f left parenthesis x right parenthesis$
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell open x cubed minus 1 greater than 0 comma 4 minus x squared not equal to 0 close parentheses end cell row cell not stretchy rightwards double arrow x left parenthesis x minus 1 right parenthesis left parenthesis x plus 1 right parenthesis greater than 0 text and end text x not equal to plus-or-minus 2 end cell row cell not stretchy rightwards double arrow x element of left parenthesis negative 1 comma 0 right parenthesis union left parenthesis 1 comma straight infinity right parenthesis comma x not equal to plus-or-minus 2 end cell end table$

$not stretchy rightwards double arrow x element of left parenthesis negative 1 comma 0 right parenthesis union left parenthesis 1 comma 2 right parenthesis union left parenthesis 2 comma straight infinity right parenthesis$

$text If end text f left parenthesis x right parenthesis equals open parentheses fraction numerator x over denominator 1 minus vertical line x vertical line end fraction close parentheses to the power of 1 divided by 2002 end exponent comma text then end text D subscript f text is end text$

maths-General

General

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Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

maths-General

General

maths-

Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

maths-General

General

maths-

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

maths-General

General

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The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

maths-General

General

Maths-

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

Differentiation is the process of determining a function's derivative. The derivative is the rate at which x changes in relation to y when x and y are two variables. A constant function has zero derivatives. For instance, f'(x) = 0 if f(x) = 8. So the derivative function is odd.

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

Maths-General

General

maths-

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

maths-General

General

maths-

$text If end text f left parenthesis x right parenthesis equals fraction numerator 1 over denominator square root of vertical line x vertical line minus x end root end fraction text then, domain of end text f left parenthesis x right parenthesis text is end text$

maths-General

General

maths-

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

maths-General

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The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

maths-General

General

maths-

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

maths-General

General

maths-

If $a greater than b greater than 0$ , then the value of $tan to the power of negative 1 end exponent invisible function application open parentheses a over b close parentheses plus tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a plus b over denominator a minus b end fraction close parentheses$ depends on

maths-General

General

maths-

$cot to the power of negative 1 end exponent invisible function application left parenthesis square root of cos invisible function application alpha end root right parenthesis minus tan to the power of negative 1 end exponent invisible function application left parenthesis square root of cos invisible function application alpha end root right parenthesis equals x$ then is equal to

maths-General

General

maths-

Number of solutions of the equation $tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 2 x plus 1 end fraction close parentheses plus tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator 4 x plus 1 end fraction close parentheses equals tan to the power of negative 1 end exponent invisible function application open parentheses 2 over x squared close parentheses$ is

maths-General

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$text If end text sec to the power of negative 1 end exponent invisible function application square root of 1 plus x squared end root plus cosec to the power of negative 1 end exponent invisible function application fraction numerator square root of 1 plus y squared end root over denominator y end fraction plus cot to the power of negative 1 end exponent invisible function application 1 over z equals pi$ $text then end text x plus y plus z$ is equal to

maths-General

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Domain of definition of the function

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Domain of definition of the function $f left parenthesis x right parenthesis equals fraction numerator 3 over denominator 4 minus x squared end fraction plus log subscript 10 invisible function application open parentheses x cubed minus x close parentheses comma text is end text$

The correct answer is: $left parenthesis negative 1 comma 0 right parenthesis union left parenthesis 1 comma 2 right parenthesis union left parenthesis 2 comma straight infinity right parenthesis$

Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

Range of the function $f left parenthesis x right parenthesis equals fraction numerator x squared plus x plus 2 over denominator x squared plus x plus 1 end fraction semicolon x element of R text is end text$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of $sin to the power of negative 1 end exponent invisible function application open parentheses log subscript 3 invisible function application x close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

The domain of the function $f left parenthesis x right parenthesis equals log subscript 3 plus x end subscript invisible function application open parentheses x squared minus 1 close parentheses text is end text$

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

If $f left parenthesis x right parenthesis equals 2 x to the power of 6 plus 3 x to the power of 4 plus 4 x squared$ , then $f to the power of straight prime left parenthesis x right parenthesis$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals log subscript 2 invisible function application open parentheses log subscript 3 invisible function application open parentheses log subscript 4 invisible function application x close parentheses close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The domain of the function $f left parenthesis x right parenthesis equals exp invisible function application open parentheses square root of 5 x minus 3 minus 2 x squared end root close parentheses$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

The value of $tan invisible function application open curly brackets cos to the power of negative 1 end exponent invisible function application open parentheses negative 2 over 7 close parentheses minus pi over 2 close curly brackets$ is

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to

$sin invisible function application open parentheses 1 half cos to the power of negative 1 end exponent invisible function application 4 over 5 close parentheses$ is equal to