Maths-
General
Easy

Question

Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

The correct answer is: Final Answer:- ∴ Area of the given verandah is 63 m2.


    Hint:-
    Area of a rectangle = length ×breadth
    Step-by-step solution:-
    From the adjacent diagram,
    Let the outer rectangle represent the verandah around the room.
    ∴ Length of the outer rectangle = length of the room + 2 (width of the verandah)
    ∴ Length of the outer rectangle = 5.5 + 2 (2.25)
    ∴ Length of the outer rectangle = 5.5 + 4.5
    ∴ Length of the outer rectangle = 10 m ........................................................... (Equation i)
    Also, breadth of the outer rectangle = breadth of the room + 2 (width of the verandah)
    ∴ breadth of the outer rectangle = 4 + 2 (2.25)
    ∴ breadth of the outer rectangle = 4 + 4.5
    ∴ breadth of the outer rectangle = 8.5 m .................................................. (Equation ii)
    Area of the outer rectangle = length × breadth
    Final Answer:-
    ∴ Area of the given verandah is 63 m2.

    ∴ Area of the outer rectangle = 10 × 8.5 ......................................................... (From Equations i & ii)
    ∴ Area of the outer rectangle = 85 m2 ............................................................ (Equation iii)
    Area of the room = length × breadth
    ∴ Area of the room = 5.5 × 4 ......................................................................... (From given information)
    ∴ Area of the room = 22 m2 .......................................................................... (Equation iv)
    Now, Area of the verandah = Area of outer rectangle - Area of the inner room
    ∴ Area of the verandah = 85 - 22 ............................................................ (From Equations iii & iv)
    ∴ Area of the verandah = 63 m2

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