Question
For thorium A =232, Z=90 at the end of some radioactive disintegration we obtain an isotope of lead with A=208 and Z=82, then the number of emitted 
particles are
The correct answer is:
Given 
Change in mass number 
No. of 
particles emitted 
Now. Eq.(i) becomes 
Further change in atomic number is 
It means atomic no. 78 is increased by 4 to make the atomic no 82.
Therefore 6
-particles and 4
particles will be emitted.
-particles and 4 particles will be emitted.Related Questions to study
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A radioactive nucleus emits -particles and 5-particles. The ratio of number of neutrons to that of protons will be
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and 
?
orbital:
Compare x and y bond lengths for the above given molecules:
and 
Compare x and y bond lengths for the above given molecules:
Compare x and y bond lengths for the above given molecules:
