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Maths-

General

Easy

Question

If $180 to the power of ring operator less than theta less than 270 to the power of 0 comma c o t space theta equals 4 divided by 3$

$\frac{3}{\sqrt{10}}$
$- \frac{2}{\sqrt{5}}$
$- \frac{1}{\sqrt{5}}$
$\frac{1}{\sqrt{5}}$

The correct answer is: $fraction numerator 3 over denominator square root of 10 end fraction$

sol. $cos space theta equals fraction numerator negative 4 over denominator 5 end fraction comma text use end text 2 sin squared space theta over 2 equals 1 minus cos space theta$

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$cot space theta equals fraction numerator 2 tan space 71 divided by 2 to the power of ring operator 0 over denominator 1 minus tan squared space 71 divided by 2 end fraction$ then $sin space 3 theta equals$

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parallel

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The cylindrical tube of as pray pump has radius, R, o neend of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the hole sis :

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A vessel with water is place don a weighing pan and it reads 600g.Now a ball ofmass40ganddensity0.80gcm-3issunkintothewater with a p in of negligible volume, as shown in figure keeping it sunk. The weight in g pan will show are a ding

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parallel

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