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General

General

Easy

Question

$I f space fraction numerator left parenthesis 2 x minus 1 right parenthesis left parenthesis x minus 1 right parenthesis squared left parenthesis x minus 2 right parenthesis cubed over denominator left parenthesis x minus 4 right parenthesis to the power of 4 end fraction greater than 0 space t h e n space x space l i e s space i n$

$(- \infty, 4)$
$(- \infty, \frac{1}{2}) \cup (2, \infty) - \{4\}$
$(\frac{1}{2}, 2)$
$n o n e o f t h e s e$

The correct answer is: $left parenthesis negative infinity comma space 1 half right parenthesis union left parenthesis 2 comma space infinity right parenthesis minus open curly brackets 4 close curly brackets$

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