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General

General

Easy

Question

$i f space fraction numerator open parentheses x squared plus 3 close parentheses open parentheses x minus 1 close parentheses to the power of 4 over denominator open parentheses x plus 1 close parentheses end fraction greater than 0 space t h e n space x element of$

$(+ 1, \infty)$
R
$(- 1, \infty) - \{1\}$
$(- 1, \infty) - \{1, - 8\}$

The correct answer is: $open parentheses negative 1 comma space infinity close parentheses minus open curly brackets 1 close curly brackets$

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