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General

General

Easy

Question

If $fraction numerator left parenthesis 2 x minus 1 right parenthesis left parenthesis x minus 1 right parenthesis squared left parenthesis x minus 2 right parenthesis cubed over denominator left parenthesis x minus 4 right parenthesis to the power of 4 end fraction greater than 0$ then x lies in

$(- \infty, 4)$
$(- \infty, \frac{1}{2}) \cup (2, \infty) - {4}$
$(\frac{1}{2}, 2)$
None of these

The correct answer is: $left parenthesis negative infinity comma space 1 half right parenthesis space union space left parenthesis 2 comma space infinity right parenthesis space minus left curly bracket 4 right curly bracket$

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