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Maths-

General

Easy

Question

If $Tan space bold A plus Tan space 2 bold A plus square root of 3 Tan space bold ATan 2 bold A equals square root of 3$ then the general solution of $A over 2 equals$

$\frac{n π}{3} + \frac{π}{9}, \forall n \in Z$
$n π + \frac{π}{9}, \forall n \in Z$
$\frac{n π}{6} + \frac{π}{18}, \forall n \in Z$
$\frac{n π}{3} + \frac{π}{4}, \forall n \in Z$

The correct answer is: $fraction numerator n pi over denominator 6 end fraction plus pi over 18 comma straight for all n element of Z$

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